目录
- 前言
- 正文
- 第一个小玩法 将集合通过Stream.collect() 转换成其他集合/数组:
- 第二个小玩法 聚合(求和、最小、最大、平均值、分组)
- 总结
前言
本身我是一个比较偏向少使用Stream的人,因为调试比较不方便。
但是, 不得不说,stream确实会给我们编码带来便捷。
正文
Stream流 其实操作分三大块 :
我今天想分享的是 收集 这part的玩法。

OK,开始结合代码示例一起玩下:
lombok依赖引入,代码简洁一点:
| 1 2 3 4 5 6 | <dependency> <groupId>org.projectlombokgroupId> <artifactId>lombokartifactId> <version>1.18.20version> <scope>compilescope> dependency> |
准备一个UserDTO.java
| 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 | /** * @Author: JCccc * @Date: 2022-9-20 01:25 * @Description: */ @Data public class UserDTO { /** * 姓名 */ private String name; /** * 年龄 */ private Integer age; /** * 性别 */ private String sex; /** * 是否有方向 */ private Boolean hasOrientation; } |
准备一个模拟获取List的函数:
| 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | private static List getUserList() { UserDTO userDTO = new UserDTO(); userDTO.setName("小冬"); userDTO.setAge(18); userDTO.setSex("男"); userDTO.setHasOrientation(false); UserDTO userDTO2 = new UserDTO(); userDTO2.setName("小秋"); userDTO2.setAge(30); userDTO2.setSex("男"); userDTO2.setHasOrientation(true); UserDTO userDTO3 = new UserDTO(); userDTO3.setName("春"); userDTO3.setAge(18); userDTO3.setSex("女"); userDTO3.setHasOrientation(true); List userList = new ArrayList<>(); userList.add(userDTO); userList.add(userDTO2); userList.add(userDTO3); return userList; } |
第一个小玩法 将集合通过Stream.collect() 转换成其他集合/数组:
现在拿List 做例子
转成 HashSet :
| 1 2 3 | List<UserDTO> userList = getUserList(); Stream<UserDTO> usersStream = userList.stream(); HashSet<UserDTO> usersHashSet = usersStream.collect(Collectors.toCollection(HashSet::new)); |
转成 Set usersSet :
| 1 2 3 | List<UserDTO> userList = getUserList(); Stream<UserDTO> usersStream = userList.stream(); Set<UserDTO> usersSet = usersStream.collect(Collectors.toSet()); |
转成 ArrayList :
| 1 2 3 | List<UserDTO> userList = getUserList(); Stream<UserDTO> usersStream = userList.stream(); ArrayList<UserDTO> usersArrayList = usersStream.collect(Collectors.toCollection(ArrayList::new)); |
转成 Object[] objects :
| 1 2 3 | List<UserDTO> userList = getUserList(); Stream<UserDTO> usersStream = userList.stream(); Object[] objects = usersStream.toArray(); |
转成 UserDTO[] users :
| 1 2 3 4 5 6 | List userList = getUserList(); Stream usersStream = userList.stream(); UserDTO[] users = usersStream.toArray(UserDTO[]::new); for (UserDTO user : users) { System.out.println(user.toString()); } |
第二个小玩法 聚合(求和、最小、最大、平均值、分组)
找出年龄最大:
stream.max()
写法 1:
| 1 2 3 4 5 6 7 8 | List userList = getUserList(); Stream usersStream = userList.stream(); Optional maxUserOptional = usersStream.max((s1, s2) -> s1.getAge() - s2.getAge()); if (maxUserOptional.isPresent()) { UserDTO masUser = maxUserOptional.get(); System.out.println(masUser.toString()); } |
写法2:
| 1 2 3 4 5 6 | List userList = getUserList(); Stream usersStream = userList.stream(); Optional maxUserOptionalNew = usersStream.max(Comparator.comparingInt(UserDTO::getAge)); if (maxUserOptionalNew.isPresent()) { UserDTO masUser = maxUserOptionalNew.get(); System.out.println(masUser.toString()); } |
效果:

输出:
UserDTO(name=小秋, age=30, sex=男, hasOrientation=true)
找出年龄最小:
stream.min()
写法 1:
| 1 2 3 4 5 | Optional minUserOptional = usersStream.min(Comparator.comparingInt(UserDTO::getAge)); if (minUserOptional.isPresent()) { UserDTO minUser = minUserOptional.get(); System.out.println(minUser.toString()); } |
写法2:
| 1 | Optional min = usersStream.collect(Collectors.minBy((s1, s2) -> s1.getAge() - s2.getAge())); |
求平均值:
| 1 2 3 | List userList = getUserList(); Stream usersStream = userList.stream(); Double avgScore = usersStream.collect(Collectors.averagingInt(UserDTO::getAge)); |
效果:

求和:
写法1:
| 1 | Integer reduceAgeSum = usersStream.map(UserDTO::getAge).reduce(0, Integer::sum); |
写法2:
| 1 | int ageSumNew = usersStream.mapToInt(UserDTO::getAge).sum(); |
统计数量:
| 1 | long countNew = usersStream.count(); |
简单分组:
按照具体年龄分组:
| 1 2 | //按照具体年龄分组 Map> ageGroupMap = usersStream.collect(Collectors.groupingBy((UserDTO::getAge))); |
效果:

分组过程加写判断逻辑:
| 1 2 3 4 5 6 7 8 | //按照性别 分为"男"一组 "女"一组 Map> groupMap = usersStream.collect(Collectors.groupingBy(s -> { if (s.getSex().equals("男")) { return 1; } else { return 0; } })); |
效果:

多级复杂分组:
| 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 | //多级分组 // 1.先根据年龄分组 // 2.然后再根据性别分组 Map>>> moreGroupMap = usersStream.collect(Collectors.groupingBy( //1.KEY(Integer) VALUE (Map>) UserDTO::getAge, Collectors.groupingBy( //2.KEY(String) VALUE (Map>) UserDTO::getSex, Collectors.groupingBy((userDTO) -> { if (userDTO.getSex().equals("男")) { return 1; } else { return 0; } })))); |
效果:

总结
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